Question

(20 POINTS!!!) An object that is 0.5 m above the ground has the same amount of potential energy as a spring that is stretched 0.5 m. Each distance is then doubled. How will the potential energies of the object and the spring compare after the distances are doubled? The gravitational potential energy of the object will be two times greater than the elastic potential energy of the spring. The elastic potential energy of the spring will be four times greater than the gravitational potential energy of the object. The elastic potential energy of the spring will be two times greater than the gravitational potential energy of the object. The potential energies will remain equal to one another.

Answer 1

C is the answer. The elastic potential energy of the spring will be two times greater than the gravitational potential energy of the object.

Answer 2

The correct answer is The elastic potential energy of the spring will be two times greater than the gravitational potential energy of the object.

The formula for Gravitational potential energy is= mgh where

m=mass

g= 9.8

h=height.

On the other hand the formula for Elastic potential energy is (1/2)KX^2

where K is the spring constant and x is the displacement of the string. By changing the values of H and X, we will see elastic potential energy will remain more.