Question

28. Jake and Claire are looking at a math problem. The problem asks them todetermine how many 42-cent stickers can be purchased with $10.• Jake divides 10 by 0.42 to determine the number of stickers.. Claire writes a multiplication equation, 0.425 = 10, and thensolves for s.Select a phrase and a value to complete the sentence evaluating Jake'sand Claire's approaches to solving the problem and providing a solution.For each box, fill in the bubble before the phrase or value that is correct.Only Jake isOnly Claire isJake and Claire are both correct; therefore, the number of stickersNeither Jake nor Claire ispurchased is© 232442052

Answer 1

EXPLANATION

#28 Let's see the facts:

Number of 0.42c stickers that could be purchased with $10:

Jake's equation:

$Number_{\text{ }}0.42cstickers=\frac{10}{0.42}=23.8\text{ }\approx24\text{stickers}$

Claire's equation:

$0.425s=10$

Isolating s:

$s=\frac{10}{0.425}=23.8\approx24\text{ stickers}$

Jake and Claire are both correct; therefore, the number of stickers is 24.