Question

How much energy is required to raise the temperature of 8.56 kg of water from 33.52oC to 61.13oC? The specific heat of water in this state is 4186 J/kg-oC.

Answer 1

In order to calculate the energy needed, we can use the formula below:

$Q=m\cdot c\operatorname{\cdot}\Delta T$

Where Q is the heat needed (in Joules), m is the mass, c is the specific heat and DeltaT is the change of temperature.

So, using the given information, we have:

$\begin{gathered} Q=8.56\operatorname{\cdot}4186\operatorname{\cdot}(61.13-33.52)\\ \\ Q=8.56\operatorname{\cdot}4186\operatorname{\cdot}27.61\\ \\ Q=989325.94\text{ J} \end{gathered}$

Therefore the energy needed is 989325.94 Joules.