Question

If sin Θ = 5 over 6 , what are the values of cos Θ and tan Θ? (2 points)



cos Θ = ± 11 over 36 ; tan Θ = ± 1 over 11
cos Θ = ± square root 11 over 6 ; tan Θ = negative 1 over 11
cos Θ = ± 11 over 6 ; tan Θ = 11 over 6
cos Θ = ± square root 11 over 6 ; tan Θ = ± 5 square root 11 over 11

Answer 1

cos² (theta) = 1 - (5/6)²
cos² (theta) = 1 - 25/36 = 11/36
cos(theta) = $\sqrt{ \frac{11}{36} }=\pm \frac{ \sqrt{11} }{6}$
tan(theta) = sin(theta) / cos (theta)=$\pm\frac{5/6}{ \sqrt{11}/6 }= \pm \frac{5}{ \sqrt{11} } =\pm \frac{5 \sqrt{11} }{11}$
Answer: D)

Answer 2

Answer:

cosΘ=±$\frac{\sqrt{11} }{6}$

tanΘ =±$\frac{5\sqrt{11} }{11}$

Step-by-step explanation:

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