The speed of 5 kg ball is 10.2 m/s
Given data:
The mass of cart 1 is m₁=3 kg.
The speed of cart 1 moving east is v₁=17 m/s.
The mass of other cart is m₂=5 kg.
Since the carts stick together, and comes to rest their final velocity is zero, i.e., v=0.
Applying the conservation of momentum between the carts as,
[tex]m_1v_1+m_2v_2=(m_1+m_2)v[/tex]Here, v₂ is the speed of 5kg cart. Since the cart 2 moving in west direction therefore v₂=-v₂.
Substitute all the values in above equation,
[tex]\begin{gathered} 3(17)+5(-v_2)=(3+5)(0) \\ v_2=10.2\text{ m/s} \end{gathered}[/tex]Thus, the speed of 5 kg ball is 10.2 m/s.
Final answer: 10.2 m/s
