The slope-intercept form of a linear equation is:
[tex]\begin{gathered} y\text{ = mx + c} \\ \text{where m is the slope} \\ \text{and c is the intercept} \end{gathered}[/tex]Given:
[tex]3y\text{ + 5x = -15}[/tex]Solution
By re-arranging the given expression, we have:
[tex]\begin{gathered} \text{Dividing through by the coefficient of y} \\ \frac{3y}{3}\text{ + }\frac{5x}{3}\text{ = }\frac{-15}{3} \\ y\text{ + }\frac{5}{3}x\text{ = -5} \\ y\text{ = -}\frac{5}{3}x\text{ - 5} \end{gathered}[/tex]