Question

What is the distance between P(–4, 3) and Q(6, 1)? Round to the nearest tenth

Answer 1

$A(x_A;\ y_A);\ B(x_B;\ y_B)\\\\distance\ between\ A\ and\ B:\\\\d=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}\\-------------------\\\\P(-4;\ 3);\ Q(6;\ 1)\\\\d=\sqrt{(6-(-4))^2+(1-3)^2}=\sqrt{10^2+(-2)^2}=\sqrt{100+4}\\\\=\sqrt{104}\approx10.2$