Question

A person has a sample of gas with a volume of 9.02L and a temperature of 585.57k. If the volume of the container is reduced to 2.24L, what will the new temperature of the gas be in Kelvin?

Answer 1

Step 1 - Understanding the relation between volume and temperature for a gas sample

There are three main variables that can change the state of a gas sample: temperature, pressure and volume. If the pressure (P) is kept constant, the volume (V) becomes proportional to the temperature (T) in K:

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

Step 2 - Substituting the values in the equation above

We know, from the exercise, that V1 = 9.02 L and T1 = 585.57 K, and V2=2.24 L. Substituting these values in the equation above:

$\begin{gathered} \frac{9.02}{585.57}=\frac{2.24}{T_2} \\ \\ T_2=\frac{2.24\times585.57}{9.02}= \end{gathered}$