Need help on these two please
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Answer:
Step-by-step explanation:
Q.1.
[tex]ln\left(4\right)+\:ln\left(x\right)=ln\left(24\right)[/tex]
apply ln rules:
[tex]ln( 4 * x) = ln (24)[/tex]
cancel ln from both sides:
[tex]4x = 24[/tex]
divide both sides by 4:
[tex]x = 6[/tex]
Q.2.
[tex]2ln\left(x\right)=ln\left(4\right)+ln\left(9\right)[/tex]
apply ln rules:
[tex]ln\left(x^2\right)=ln\left(4*9\right)[/tex]
cancel ln from both sides:
[tex]x^2 = 36[/tex]
[tex]x = \pm6[/tex]
as ln cannot be negative:
[tex]x = 6[/tex]