Question

use trigaonamets functions as nessary to find the missing parts the triangle

Answer 1

Given a right angle triangle:

As shown on the acute angles is 21

So,

$\begin{gathered} \cos \text{ 21=}\frac{adjacent}{\text{hypotenuse}}=\frac{6.4}{H} \\ \\ H=\frac{6.4}{\cos 21}=6.855 \end{gathered}$

And:

$\begin{gathered} \tan 21=\frac{opposite}{\text{adjacent}}=\frac{y}{6.4} \\ \\ y=6.4\cdot\tan 21=2.457 \end{gathered}$

the third angle of the triangle =

$90-21=69$