Question

Drag the expressions in order from least to greatest value.

Answer 1

$1\frac{7}{8}=\frac{1\cdot8+7}{8}=\frac{15}{8}$$1\frac{7}{8}-\frac{1}{4}=\frac{15}{8}-\frac{1}{4}=\frac{15-1\cdot2}{8}=\frac{13}{8}$$1\frac{1}{8}=\frac{1\cdot8+1}{8}=\frac{9}{8}$$1\frac{1}{8}+\frac{1}{4}=\frac{9}{8}+\frac{1}{4}=\frac{9+1\cdot2}{8}=\frac{11}{8}$$1\frac{1}{2}=\frac{1\cdot2+1}{2}=\frac{3}{2}$$1\frac{1}{2}-\frac{5}{8}=\frac{3}{2}-\frac{5}{8}=\frac{3\cdot4-5}{8}=\frac{7}{8}$

Then, from least to greatest value, the order is:

$1\frac{1}{2}-\frac{5}{8}$$1\frac{1}{8}+\frac{1}{4}$$1\frac{7}{8}-\frac{1}{4}$