Question

In a bike race, a sport person starts his bike from rest and maintains a constant acceleration of 3 m/s2 for 8 seconds, and then a constant acceleration of 2 m/s2 for another 8 seconds. Determine the acquired velocity of the bike.

Answer 1

Answer:

40 m/s

Explanation:

First, we need to calculate the velocity after 8 seconds, so we will use the following equation:

v₂ = v₁ + at

Where v₁ is the initial velocity, so v₁ = 0 m/s, a is the acceleration a = 3 m/s² and t is the time, so t = 8s. Replacing the values, we get:

v₂ = 0 m/s + (3 m/s²)(8s)

v₂ = 0 m/s + 24 m/s

v₂ = 24 m/s

Then, it accelerates for another 8 seconds with a = 2 m/s², so the acquired velocity v₃ is equal to:

v₃ = v₂ + at

v₃ = 24 m/s + (2 m/s²)(8 s)

v₃ = 24 m/s + 16 m/s

v₃ = 40 m/s

Therefore, the acquired velocity of the bike is 40 m/s