Question

PLEASE HELP ME!!!!!!!



Four different coins are used in Australia with values of 5, 10, 20, and 50 cents. The Australian coins in Farmer Tim's pocket have a total value of $3.95, and he has at least one of each coin. What is the smallest number of coins that he could have in his pocket?

Answer 1

6 50 cent coins
1 5 cent coin
10. 9 cent coins
=17 coins

Answer 2

Answer:

11

Step-by-step explanation:

Since Farmer Tim has one of each coin, 50+20+10+5=85 cents are accounted for, leaving 395 - 85 = 310 cents for the remaining coins. We can try minimizing the number of coins that add up to 310 cents by using as many large denominations as possible.

The largest denomination is 50 cents, so we can take six 50 cent coins, which add up to 6 times 50 = 300 cents. We then can take one 10 cent coin. Thus, we have a combination of seven coins that up to 310 cents.

Therefore, the smallest number of coins that Farmer Tim could have is 4 + 7 = 11.