Question

11) -3(1 + 6r) = 14 - r

Answer 1

$-3(1+6r)=14-r$

Distributing over parentheses,

$\begin{gathered} -3\cdot1+(-3)\cdot6r=14-r \\ -3-18r=14-r \end{gathered}$

Adding r at both sides,

$\begin{gathered} -3-18r+r=14-r+r \\ -3-17r=14 \end{gathered}$

Adding 3 at both sides,

$\begin{gathered} -3-17r+3=14+3 \\ -17r=17 \end{gathered}$

Dividing by -17 at both sides,

$\begin{gathered} \frac{-17r}{-17}=\frac{17}{-17} \\ r=-1 \end{gathered}$