Question

If I have 5 blue balls, 3 green balls, and 2 red balls in a container and we draw one ball from the container at a time, what is the probability of pulling a green ball followed by 2 blue balls out of the container?

Answer 1

Answer:

The probability of pulling a green ball followed by 2 blue balls out of the container is 0.0833.

Step-by-step explanation:

Given:

The container consists of 5 Blue balls, 3 Green Balls and 2 Red balls.

That is the total number of balls is 10.

Assuming that the balls are drawn without replacement.

The probability of pulling a green ball followed by 2 blue balls out of the container is = P (Green)  × P (Blue) × P (Blue)

                    $=\frac{3}{10}\times\frac{5}{9}\times \frac{4}{8}\\=0.0833$

Thus, the probability of pulling a green ball followed by 2 blue balls out of the container is 0.0833.