Question

balloon 670 meters away angle 42degrees the higher balloon is 945 away angle 36 degrees how much higher is the balloon on the right than the left

Answer 1

$\begin{gathered} \cos \theta=\frac{945}{x} \\ x=\frac{945}{\cos (36)}=1168.084239 \\ h1=\sqrt[]{1168.084239^2-945^2}=686.582689m \end{gathered}$$\begin{gathered} \cos \theta=\frac{670}{y} \\ y=\frac{670}{\cos (42)} \\ y=901.5739288 \\ h2=\sqrt[]{901.5739288^2-670^2}=603.2707097m \end{gathered}$

Answer:

$h1-h2=686.582689-603.2707097=83.31198832m$