Question

ements Us Question 4 A 4 in. 65° В Find the area of the sector formed by Z(ABC) in 2 Question Help: 0 Video

Answer 1

Since 65 is equal to 13pi/36, then the area is:

$(4^2)(\frac{13\pi}{36})(\frac{1}{2})=8(\frac{13\pi}{36})=\frac{26\pi}{9}=9.076in^2$