Question

Three forces are exerted on an object placed on a slope in the figure. The forces are measured in Newton (N).
1. Assuming that forces are vectors, what is the component of the net force F⃗net=F⃗1+F⃗2+F⃗3 parallel to the slope?
2. What is the component of F⃗net perpendicular to the slope?
3. What is the magnitude of F⃗net?
4. What is the direction of F⃗net?

Answer 1

The component of the net force that is parallel to the slope is the friction force. It is the force due to the friction present between the object and the surface of the slope. The force perpendicular to the slope is called the normal force and it is the contact force exerted by the object to the surface of the slope.

Answer 2

Answer:

1. Component = $F - mgsin\theta - \mu R$

2. Normal

3. $F_{up} - F_{friction}$

4 . upwards

Explanation:

1. The diagram on a slope shows the forces acting on an object. There a three sets of forces that are on the object. One is the normal force, N. The other one is the pulling force, which shall be called .

The last component is the force acting on the object due to friction. this is given as $F_{total} = mgsin\theta$

2. The perpendicular force is the normal. It is given as N

3. The magnitude of the Fnet is the difference in all the forces.

4. Overall, the net force will be upwards as the object is being pulled in that direction.