First, we use the area formula for a circle
[tex]A=\pi(r)^2[/tex]Where r = 2.5 m because it's half the diameter.
[tex]A=\pi(2.5m)^2=\pi(6.25m^2)[/tex]Then, we use pi = 3.14 and divide by two because they are asking for the semi-circle (half).
[tex]A_{\text{semi}}=\frac{3.14(6.25)}{2}m^2\approx9.8m^2[/tex]