Question

(1/8) raised to -x ppwer= 64 raised to x powerI'll upload a picture

Answer 1

x = 0

Explanation:$(\frac{1}{8})^{-x}=64^x$$\begin{gathered} \frac{1}{8\text{ }}\text{ = }\frac{1}{2^3}\text{ } \\ \text{Rule: }\frac{1}{a^b}=a^{-b} \\ so,\text{ }\frac{1}{2^3}=2^{-3} \\ (\frac{1}{8\text{ }})^{-x}=(\frac{1}{2^3})^{-x}\text{ = }(2^{-3})^{-x} \\ =2^{3x} \end{gathered}$$\begin{gathered} 64=2^6 \\ 64^x=(2^6)^x=2^{6x} \\ (\frac{1}{8})^{-x}=64^x \\ 2^{3x}\text{ = }2^{6x} \\ \text{base cancels out:} \\ 3x\text{ = 6x} \end{gathered}$$\begin{gathered} 3x\text{ - }6x\text{ = 0 } \\ -3x\text{ = 0} \\ \text{divide both sides by -3:} \\ \frac{-3x}{-3}\text{ = }\frac{0}{-3} \\ x\text{ = 0} \end{gathered}$