The concentration on lead will be 47.25 × 10⁻³ g/L
Molarity also known as molar concentration refers to the number of moles of solute per liter of solution. The formula for molarity is: M = n /v.
According to the given question:
M₁ = [tex]\frac{n}{V_{1} }[/tex]
V₁ = 81 ml or 81 × 10⁻³ ( volume of solution)
M₁ = 63 × 10 ⁻⁶
Since, M₁V₁ = M₂V₂
= 63 × 10⁻⁶ × 81 × 10⁻³ = M₂ × 108 × 10⁻³
M₂ = 47.25 × 10⁻³
Hence, the molar concentration of lead for the new volume will change to 47.25 × 10⁻³ g/L
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