Question

Calculate the total capacitance of three capacitors 30µF, 20µF & 12µF connected in parallel across a d.c supply

Answer 1

Consider that the equivalent capacitance of three capacitors C1, C2 and C3 in parallel is given by:

$C=C_1+C_2+C_3$

In this case:

C1 = 30µF

C2 = 20µF

C3 = 12µF

Replace the previous values into the formula for C and simplify:

$C=30\mu F+20\mu F+12\mu F=62\mu F$

Hence, the total capacitance is 62µF