Respuesta :

Answer:

ΔV=V1-V2 = 27692307.69volts

Explanation:

Hello! Let's solve this!

The formula to calculate the power difference is

ΔV=V1-V2

V = k * (q / r)

k is a constant that equals [tex]k=9*10^{9}N*m^{2}/C^{2}[/tex]

The data we have are:

[tex]k=9*10^{9}N*m^{2}/C^{2}[/tex]

r = 0.0013m

[tex]q1=40*10^{-6}C\

F=15*10^{-6}  N[/tex]

From the following formula we can calculate how much q2 is

F = k * (q1 * q2 / r2)

q2 = (F * r2) / (k * q1)

q2 = (15*10^{-6}  N[/tex] * 0.00132) / (9*10^{9}N*m^{2}/C^{2}[/tex]  *40*10^{-6}C\)

[tex]q2=7.0417x^{-17}C[/tex]

Now we calculate with q1 and q2, V1 and V2 respectively.

V1 = (9*10^{9}N*m^{2}/C^{2}[/tex]  * 40*10^{-6}C\) /0.0013m

V1 = 27692307.69 volts

V2 = (9*10^{9}N*m^{2}/C^{2}[/tex]  * 7.0417x^{-17}C[/tex]) /0.0013m

[tex]V2=4.875*10^{-4}volts[/tex]

Then we solve the potential difference:

V1-V2 = 27692307.69 volts-4.875*10^{-4}volts[/tex]

ΔV=V1-V2 = 27692307.69volts

Answer:

C. 4.9 × 10-4 V

Explanation:

ΔV = E d  

E = force/charge = 15 µN / 40 µC = 0.375 N/C

ΔV = 0.375 N/C * 0.0013 m = C. 4.9 × 10-4 V

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