Question

Consider the following equilibrium:H2 (g) + I2 (g) ↔ 2 HI (g)At equilibrium [ H2 ] = 0.00220 mol/L, [ I2 ] = 0.00220 mol/L and [ HI ] = 0.0156mol/L. The value of Keq is ______.Select one:a.3.10 X 10 - 4b.5.03 X 101c.1.99 X 10 - 2d.3.22 X 103

Answer 1

Explanation:

To solve this question, we need to use the following formula:

Keq = [HI]^2/[H2].[I2]

Here we have:

[HI] = 0.0156 mol/L

[H2] = 0.00220 mol/L

[I2] = 0.00220 mol/L

Keq = (0.0156)^2/(0.00220).(0.00220)

Keq = 2.4336x10^-4/4.84x10^-6

Keq = 50.3

Answer: b. 5.03 X 10^1