Respuesta :

[tex]4t^3+\frac{7}{2}t^2-5t+C[/tex]

Explanation

[tex]\int (12t^2+7t-5)\text{ d t}[/tex]

Step 1

separate the terms

[tex]\int (12t^2+7t-5)\mathrm{d}t=\int 12t^2dt+\int 7tdt-\int 5\text{ d t}[/tex]

then, solve each integer:

remeber

[tex]\int ax^ndx=\frac{(a)}{n+1}x^{n+1}[/tex]

hence,

[tex]\begin{gathered} \int 12t^2dt+\int 7tdt-\int 5\text{ d }t=(\frac{12}{3})t^{2+1}+\frac{7}{2}t^{1+1}-\frac{5}{1}t^{0+1} \\ \int 12t^2dt+\int 7tdt-\int 5\text{ d }=4t^3+\frac{7}{2}t^2-5t+C \end{gathered}[/tex]

I hope this helps you

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