erickarrevillaga erickarrevillaga
  • 21-03-2014
  • Mathematics
contestada

4a²+4a   x a²-5a
a²-25         8a

Respuesta :

deathstrike001
deathstrike001 deathstrike001
  • 21-03-2014
(4a^2 + 4a)/(a^2-25) x (a^2-5a)/8a
Factor the possible ones to be easier
[4a(a+1)]/[(a-5)(a+5)] x [a(a-5)/8a]
Cancel the a-5
[4a(a+1)]/[a+5)] x a/8a
cancel the 4a and 8a(8a becames 2)
[a+1]/[a+5] x a/2
now multiply
[a(a+1)]/[2(a+5)]<---- can be the answer or:
(a^2+a)/(2a+10)
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