Question

parallelogram QRS has diagonals PR and SQ that intersect at T QT equals 21 and TR equals 13 find the length of QS

Answer 1

Since it is a parallelogram then it is true that

That is, the segments are congruent

$\begin{gathered} AE\cong EC \\ DE\cong EB \\ AD\cong BC \\ AB\cong DC \\ \end{gathered}$

So, in this case, you have

$\begin{gathered} QT\cong TS \\ \text{ Then} \\ QT=21 \\ TS=21 \end{gathered}$$\begin{gathered} QS=QT+TS \\ QS=21+21 \\ QS=42 \end{gathered}$

Therefore, the length of QS is 42.