A lot is in the shape of a triangle. One side is 100 ft longer than the shortest side, while the third side is 700 ft longer than the shortest side. The perimeter of the lot is 2900 ft. Find the lengths of the lot.The lengths of the sides of the lot are ___,___, and ___ (ft, ft^2, or ft^3.)

Respuesta :

We have the next information

x= the shortest side measure

y= the second side measure

y=x+100

z= the third side measures

z=x+700

We know also that the perimeter is 2900 ft

Therefore the equation for the perimeter of the triangle will be

[tex]P=x+y+z[/tex][tex]2900=x+x+100+x+700[/tex]

we sum like terms

[tex]2900=3x+800[/tex]

then we isolate the x

[tex]3x=2900-800[/tex][tex]3x=2100[/tex][tex]x=\frac{2100}{3}=700[/tex]

therefore

x=700ft

y=700+100=800ft

z=700+700=1400ft

The lengths of the sides of the lote are 700 ,800, and 1400 ft,

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