Question

Elizabeth brought a box of donuts to share. there are two dozens (24) donuts in the box. all identical in size shape and color. four are jelly filled, six are lemon filled and 14 are custard filled. you randomly select one donut and eat it. and select another donut. find the probability of selecting two custard filled donuts in a row

Answer 1

Total donut = 24

donut with lemom=6

donut with jelly=4

donut with custard = 14

$\begin{gathered} \text{Probability =}\frac{Required\text{ outcome}}{\text{Total outcome}} \\ \end{gathered}$$\begin{gathered} \text{Hence} \\ \text{prb(custard) = }\frac{14}{24}=\frac{7}{12} \end{gathered}$

Since you are taking donuts and eating them. Hence you are not replacing the donut you have taken.

The probability of taking a second custard without replacement will be

$\text{Prb(custard)}=\frac{13}{23}$

Hence the probability becomes

$\frac{7}{12}\times\frac{13}{23}=\frac{91}{276}$

The probability of selecting two custard-filled donuts in a row is 91/276