Question

please help and explain I have no idea what e and in meanssimplify this

Answer 1

Given

$(e^{2-\sqrt{3}})^{2+\sqrt{3}}$

To simplify.

Explanation:

It is given that,

$(e^{2-\sqrt{3}})^{2+\sqrt{3}}$

Since

$(a^x)^y=a^{xy}$

That implies,

$\begin{gathered} (e^{2-\sqrt{3}})^{2+\sqrt{3}}=e^{(2-\sqrt{3})(2+\sqrt{3})} \\ =e^{4-3} \\ =e^1 \\ =e \end{gathered}$

Hence, the answer is e.