Question

Which of the following would be equivalent to 11 to the 8th power over 11 to the 3rd power

Answer 1

$Use\ \dfrac{a^n}{a^m}=a^{n-m}\\\\\dfrac{11^8}{11^3}=11^{8-3}=\boxed{11^5}$

Answer 2

Answer:

The equivalent equation can be written as: 11^5

Step-by-step explanation:

There is a relationship that can be very usefull here:

(a^b)*(a^c) = a^(b+c)

(a^b)/(a^c) = a^(b-c)

Then, if we have:

(11^8)/(11^3) = 11^(8-3) = 11^5

This means that 11^5 is equivalent to 11 to the 8th power over 11 to the 3rd power