Question

What Celsius temperature, T2 , is required to change the volume of the gas sample in Part A ( T1 = 35 ∘C , V1 = 1260 L ) to a volume of 2520 L ? Assume no change in pressure or the amount of gas in the balloon.

Answer 1

Answer:

70 degree celsius

Explanations:

According to Charle's law, the volume of a given mass of gas is directly proportional to absolute temperature provided that the pressure is constant. Mathematically;

$\begin{gathered} v\alpha T \\ v=kT \\ k=\frac{v_1}{T_1}=\frac{v_2}{T_2} \end{gathered}$

where

v1 and v2 are the initial and final volume respectively

T1 and T2 are the initial and final temperature respectively

Given the following parameters

$\begin{gathered} v_1=1260L \\ v_2=2520L \\ T_1=35^0C \end{gathered}$

Required

Final temperature T2

Substitute the given parameters into the formula to have:

$\begin{gathered} T_2=\frac{v_2T_1}{v_1} \\ T_2=\frac{2520\times35}{1260} \\ T_2=70^0C \end{gathered}$

Hence the celsius temperature T2 required is 70 degree celsius