Question

find a formula for the nth term of the arithmetic sequence. First term -12 common difference 4an = 4n + [?]

Answer 1

Nth term of sequence = a + ( n- 1) d

First term, a = -12

common difference, d = 4

$\begin{gathered} T_{n\text{ = a + ( n- 1 ) d}} \\ Tn\text{ = -12 + ( n- 1) 4} \\ \text{ = -12 + 4n -4} \\ \text{ = 4n -12 -4} \\ \text{ = 4n -16} \\ =\text{ 4n + ( -16)} \end{gathered}$