Question

Let h be the function defined by h(x) =2x+3. Find the range of h.

Answer 1

$\text{Range of h = (-}\infty,\text{ }\infty)$

Explanation:

h(x) =2x+3

let h(x) = y

y = 2x + 3

Solve by interchanging x an y:

x = 2y + 3

Make y the subject of formula:

$\begin{gathered} 2y\text{ = x-3} \\ y\text{ = }\frac{x-3}{2} \end{gathered}$

Fromthe above, x can take on the value of any number. This is because no real number will make x undefined.

The range of h(x) =2x+3 will span from negative infinity to positive infinity.

$\text{Range of h = (-}\infty,\text{ }\infty)$