Hello I need help finding the acceleration of this pulley .

Answer:
3.267 m/s²
Explanation:
Given the mass m1 = 20 kg and m2 = 10 kg, we can find the acceleration using the following equation:
[tex]a=\frac{F_{\text{net}}}{(m_1+m_2)}[/tex]The forces acting on the system are the weights of each mass. So, the net force will be equal to the differences between these weights, then:
[tex]a=\frac{(m_1-m_2)g}{m_1+m_2}[/tex]Therefore, the acceleration of the system will be:
[tex]\begin{gathered} a=\frac{(20\operatorname{kg}-10\operatorname{kg})(9.8m/s^2)}{(20\operatorname{kg}+10\operatorname{kg})} \\ a=\frac{10\operatorname{kg}(\frac{9.8m}{s^2})}{30\operatorname{kg}} \\ a=3.267m/s^2 \end{gathered}[/tex]So, the acceleration will be 3.267 m/s², where m1 is moving down and m2 is moving up.