Question

A force of 9.00 newtons acts at an angle of 19.0 to the horizontal. What is its component in the horizontal direction?

Answer 1

Solution

In this question we have given,

Force, F=9N

angle,α=19degree with horizontal

therefore,

Component of force in horizontal direction is given as

$F_{x} =F\times Cos\alpha$

$F_{x} =9\times Cos19$

$F_{x} =9\times .946$

$F_{x} =8.51N$