SOLUTION
A. how far the ball has fallen after 1 second
We will use the function to do this, using t = 1. This becomes
[tex]\begin{gathered} h=-16t^2+6 \\ h=-16(1)^2+6 \\ h=-16+6 \\ h=-10 \end{gathered}[/tex]So in 1 second, the ball has fallen 10 units
B. We will also find the depth of the well using the function. But here,
t = 3.2 seconds
[tex]\begin{gathered} h=-16t^2+6 \\ h=-16(3.2)^2+6 \\ h=-16\times10.24+6 \\ h=-163.84+6_{} \\ h=-157.84 \end{gathered}[/tex]So the depth = 157.84 units