The amount of exhaust heat discharged per hour from the plant which produces electric energy at the rate of 1. 5 gw, is 9.36×10¹⁹ J/h.
The heat is discharged per hour is equal to the different of total power and actual power.
The plant produces electric energy at the rate of 1. 5 gw. Let assume the efficiency of this power plant is 64% between the temperature of 660 degree C to 330 degree Celsius.
Thus, the maximum efficiency is,
[tex]\eta_{max}=1-\dfrac{660+273}{330+273}\\\eta_{max}=0.55[/tex]
The total power is,
[tex]P_t=\dfrac{P_A}{\eta_{max}\times0.64}\\P_t=\dfrac{1.5}{0.55\times0.64}\\P_t=4.26\rm\; GW[/tex]
Thus, the heat discharged per hour is,
[tex]Q=4.26-1.5\\Q=2.76\text{GW}\\[/tex]
Multiply the value with 3600 to convert it in s/h,
[tex]Q=2.76\times10^9\times3600\text{ J/h}\\Q=9.36\times10^{19}\text{ J/h}\\[/tex]
Thus, the amount of exhaust heat discharged per hour from the plant which produces electric energy at the rate of 1. 5 gw, is 9.36×10¹⁹ J/h.
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