Question

The table below shows the results of a survey asking 48 studentswhat type of pet they prefer.Pet SurveyPreferred Pet # of StudentsDog 20Cat 16Other Pet 5No Pet 7If one student in the survey is selected at random, what is theprobability the student will prefer a cat or a dog?Leave your answer in fraction form.

Answer 1

Answer:

$P(A\text{ or B)=}\frac{3}{4}$

Step-by-step explanation:

The probability of an event is represented by the following equation;

$P(A)=\frac{\text{ Number of favorable outcomes}}{\text{Number of total possible outcomes}}$

Since the events are mutually exclusive, they are called disjoint events. It is given as:

$P(A\text{ or B)=P(A)+P(}B)$

Then, the probability of selecting randomly a student that prefers a cat or a dog:

$\begin{gathered} P(A\text{ or B)=}\frac{16}{48}+\frac{20}{48} \\ P(A\text{ or B)=}\frac{36}{48} \\ P(A\text{ or B)=}\frac{3}{4} \end{gathered}$