Question

The area of a sector of a circle with a central angle

Answer 1

The area sector of a circle is

$A=\frac{\theta}{360}(\pi r^2)$

where θ = central angle

r = radius of the circle

From the problem, the area is 9 ft^2 and the central angle is 60 degrees

The radius will be :

$\begin{gathered} 9=\frac{60}{360}(\pi r^2) \\ 9(360)=60\pi r^2 \\ \frac{9(360)}{60\pi}=r^2 \\ r=\sqrt[]{\frac{9(360)}{60\pi}} \\ r=4.146 \end{gathered}$

The answer rounded to the nearest tenth is 4.1 ft