Question

An oscillator is formed of a mass m = 2 kg attached to a spring having a spring constant k = 200 N/m. The frequency of oscillation is equal to:

Answer 1

Given,

The mass attached to the spring, m=2 kg

The spring constant of the spring to which the mass is attached, k=200 N/m

The time of the oscillation of the oscillator is given by,

$T=2\pi\sqrt[]{\frac{m}{k}}$

The frequency is related to the period of the oscillator as,

$f=\frac{1}{T}$

Thus the frequency of the oscillator is given by,

$f=\frac{1}{2\pi}\sqrt[]{\frac{k}{m}}$

On substituting the known values in the above equation,

$\begin{gathered} f=\frac{1}{2\pi}\sqrt[]{\frac{200}{2}} \\ =1.59\text{ Hz} \end{gathered}$

Thus the frequency of oscillation of thus formed oscillator is 1.59 Hz