Respuesta :

The center of the circle is (0, 2) and the radius is √3

The equation of a circle is;

[tex]r^2=(x-h)^2+(y-k)^2[/tex]

In this case, we have:

[tex]3=x^2+(y-2)^2[/tex]

Then:

[tex]r^2=3\Rightarrow r=\sqrt[]{3}^{}[/tex]

r is the radius, then we know that already.

Now the center is (h, k) from the equation of a circle, above

In this case, the number that is resti

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