The center of the circle is (0, 2) and the radius is √3
The equation of a circle is;
[tex]r^2=(x-h)^2+(y-k)^2[/tex]In this case, we have:
[tex]3=x^2+(y-2)^2[/tex]Then:
[tex]r^2=3\Rightarrow r=\sqrt[]{3}^{}[/tex]r is the radius, then we know that already.
Now the center is (h, k) from the equation of a circle, above
In this case, the number that is resti