The sum of 3x^2+x+8 and x^2-9 can be expressed as:

Answer:
[tex]4x^2+x-1[/tex]Explanation:
Given the polynomials:
[tex]3x^2+x+8\; and\; x^2-9[/tex]Their sum will be:
[tex]\begin{gathered} (3x^2+x+8)+(x^2-9) \\ =3x^2+x^2+x+8-9 \\ =4x^2+x-1 \end{gathered}[/tex]