Question

What is 36-8z in my Reverse Distribution Factoring Algebraic Expressions

Answer 1

$a^2-b^2=(a+b)(a-b) \\ \\\texttt{Here is possible factorization :} \\ \\ 36-8z \\ =6^2- \sqrt{8z} ^2 \\ \boxed{=(6- \sqrt{8z} )(6+ \sqrt{8z} )}$