Respuesta :

Ìn a circle the sum of all the central angles sum 360º.

Then, for the given circle:

[tex]m\angle IFJ+m\angle JFG+m\angle GFH+m\angle HFI=360º[/tex][tex](x+35º)+(x+16º)+(55º)+(2x-70º)=360º[/tex]

You use the equation above to find the value of x:

[tex]\begin{gathered} x+35+x+16+55+2x-70=360 \\ 4x+36=360 \\ 4x+36-36=360-36 \\ 4x=324 \\ \frac{4}{4}x=\frac{324}{4} \\ \\ x=81 \end{gathered}[/tex]

With the value of x you find the measure of angle IFJ:

[tex]m\angle IFJ=x+35=81+35=116º[/tex]Then, the measure of angle IFJ is 116º
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