To find the slope of a line parallel to the equation 8a + 10y = 60, we need to rewrite the equation in slope-intercept form, which is y = mx + b, where m is the slope.
Given equation: 8a + 10y = 60
First, isolate y:
10y = -8a + 60
y = -8/10*a + 6
y = -4/5*a + 6
Now, the slope of the given line is -4/5.
For lines that are parallel, their slopes are the same. Therefore, the slope of a line parallel to this one is also -4/5.
So, the slope of a line parallel to the equation 8a + 10y = 60 is -4/5.
