I need help with this please. Find the line equation.

We need to find the line equation. From the given picture, we can choose 2 points along the line, for instance,
[tex]\begin{gathered} (x_1,y_1)=(0,-6) \\ (x_2,y_2)=(4,0) \end{gathered}[/tex]The slope of the line is given by
[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{0-(-6)}{4-0}[/tex]which gives
[tex]m=\frac{6}{4}=\frac{3}{2}[/tex]So, the line equation has the form
[tex]y=mx+b\longrightarrow y=\frac{3}{2}x+b[/tex]We can find the y-intercept b by substituting the point (0,-6) into the last result, that is,
[tex]\begin{gathered} -6=\frac{3}{2}(0)+b \\ \text{then} \\ b=-6 \end{gathered}[/tex]Then, the line equation is
[tex]y=\frac{3}{2}x-6[/tex]Now, by multiplying both sides by 4, we get
[tex]4y=6x-24[/tex]By subtracting 6x to both sides, we have
[tex]4y-6x=-24[/tex]and by multiplying both sides by -1, we obtain
[tex]6x-4y=24[/tex]By comparing with the given options, the answer is the second option on the left hand side: 6x - 4y = 24