For this type of question, first, we set the following equation:
[tex]y=5x^{\frac{1}{5}}-2[/tex]Then, we exchange y and x:
[tex]x=5y^{\frac{1}{5}}-2[/tex]Now, we solve the above equation for y:
[tex]\begin{gathered} x+2=5y^{\frac{1}{5}} \\ y^{\frac{1}{5}}=\frac{x+2}{5} \\ y=(\frac{x+2}{5})^5 \end{gathered}[/tex]Answer:
[tex]A^{-1}(x)=(\frac{x+2}{5})^5[/tex]