Given,
Percentage of baskets jai make is 28%.
The number of free thorws are 120.
The number of basket likely made by jai in 120 free throws is,
[tex]\begin{gathered} \text{Number of basket = 28\% of total fr}e\text{ throws} \\ =28\text{ \% of 120} \\ =\frac{28}{100}\times120 \\ =33.6 \\ \approx37 \end{gathered}[/tex]
The number of basket he makes is approximately 37.
a) 1% of 120 is,
[tex]1\text{ \% of 120 = }\frac{\text{1}}{100}\times120=1.2[/tex]
b) 10% of 120 is,
[tex]10\text{ \% of 120 = }\frac{\text{1}0}{100}\times120=12[/tex]
c) 20% of 120 is,
[tex]20\text{\% of 120 = }\frac{\text{2}0}{100}\times120=24[/tex]
d) 8% of 120 is,
[tex]8\text{\% of 120 = }\frac{\text{8}}{100}\times120=9.6[/tex]
