Question

Ammonia is produced by the reaction of hydrogen and nitrogen as follows:N2(g)+3H2(g)→2NH3(g)ammoniahow many moles of H2 are needed to react with 0.55 mol of N2 ?

Answer 1

Answer:

We have the following chemical reaction:

$N_2(g)+3H_2(g)\rightleftarrows2NH_3(g)$

As we can see the equation is balanced because we have the same number of atoms of each element on each side of the equation:

2 nitrogen atoms

6 hydrogen atoms

Now, to answer the question we look at the balanced equation and see that for every mol of N2 that reacts, we need 3 moles of H2 to react. So we calculate the number of moles of H2 needed to react with 0.55 mol of N2 as follows:

$n_{H_2}=0.55\text{ mol}_.\frac{3mol_{H_2}\text{ }}{1mol_{N_2}}=1.65\text{ mol}$

So the answer is 1.65 mol of H2.